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10.2

Solution. The errors are found using the values for f(xk) and ek given in Table 1.1

TABLE 1.1

xk yk f(xk) = 8.6 - 1.6xk |ek| ek2

-1 10.0

0 9.0

1 7.0

2 5.0

3 4.0

4 3.0

5 0.0

6 -1.0

0.2 0.04

8.6 0.4 0.16

7.0 0.0 0.00

5.4 0.4 0.16

3.8 0.2 0.04

2.2 0.8 0.64

0.6 0.6 0.36

-1.0 0.0 0.00

2.6 1.40

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