4. Iterative Method

Example 3

(a) Jacobi iteration

x1(k+1) = (7 + x2 (k) - x3 (k) )/4

x2(k+1) = (21 + 4x1(k) + x3(k) )/8

x3(k+1) = (15 + 2x1(k) - x2(k))/5

x1(1) = 1.750, x2(1) = 3.375, x3(1) = 3.000

x1(2) = 1.844, x2(2) = 3.875, x3(2) = 3.025

x1(3) = 1.962, x2(3) = 3.925, x3(3) = 2.962

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